how do i solve this equation?

2008-12-08 8:18 am

20t-3t^2 all over 3 equals 0

回答 (4)

2008-12-08 8:40 am

✔ 最佳答案

Solve by completing the square:
t² - (20/3)t + 100/9 = 100/9
(t - 10/3)² = 100/9
√[(t - 10/3)²] = √(100/9)
t - 10/3 = 25/3
t = 35/3

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2008-12-08 8:20 am

t = 0, 20/3

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2008-12-08 10:55 am

(20t - 3t^2)/3 = 0
20t - 3t^2 = 3(0)
t(20 - 3t) = 0

t = 0

20 - 3t = 0
-3t = -20
t = -20/-3
t = 20/3

∴ t = 0 , 20/3

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2008-12-08 8:31 am

20 t - 3 t ² = 0
t ( 20 - 3t ) = 0
t = 0 , t = 20 / 3

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