Is resistance related to heat produced?

2008-12-09 5:56 am
If a wire has a more resistance, does it mean that the wire also produce more heat than a less resistance one when a current passes through them respectively? Please also explain. Thanks
更新1:

About the rules P=V2/R and P=I2/R, is it P=V2/R is only for parallel curcuits and P=I2/R for series?

回答 (4)

2008-12-09 6:34 am
✔ 最佳答案
There are two case affect the heat.
In a parallel circuit,the voltage passing though the two resistors are the same.
By P=V^2/RIf the resistance is more higher,the power will be less.
Therefore,higher resistance cause lower heat energy in parallel circuit.

In a series circuit,the current passing though the two resistors are the same.
By P=I^2R
If the resistance is more hight ,the power will be higher.
Therefore,higher resistance cause higher heat energy in series circuit.

2008-12-14 11:07:51 補充:
條式係I^2R,唔係I^2/R
參考: me
2008-12-13 10:01 am
both P=V2/R and P=I2/R apply for parallel and series curcuits!
Just be aware that V need to be the potential difference across a certain
resistor and I be the current passing through it when you apply these two
formula
2008-12-11 11:58 pm
Forget about parallel or serial circuits. Power = heat generated
Just calculate each wire's resistance and current and get the power P=I2/R, thus the heat generated
2008-12-11 10:41 pm
Heat generated at the resistor = I^2*R. If the same current pass through resistors for two different cases, more heat will be generated for the case with higher resistance. However, you usually get a higher current I, if you use a smaller value of resistor.


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