what is 56 times 90 minus 10 plus 67 times 81?

(56 x 90)- 10 +( 67 x 81)
=( 5040 - 10) + 5427
= (5030 + 5427)=10457

(56 x 90) - 10 + (67 x 81)
5040 - 10 + 5427
5030 + 5427
10457

To answer this question you must define what it is.

It could be (56x90)-10+(67x81)
or (56x90)-[10+(67x81)]
or [(56x(90-10)+67x81)
or . . . ..!
So your answer may be right if you use the combination to get that answer - but it is not the only answer!!

You must define the question and then answer it!

56*90-10+67*81
=5040-10+5427
=5030+5427
=10457
(using BODMAS rule)

the answer is 10457.
this is followed by the principal of BODMAS.
B- bracket
O- off
D- divide
M- multiply
A- add
S- subtract

56 x 90 - 10 + 67 x 81
therefore, multiply must go first

= 5040 - 10 + 5427
than you subtract,
= 5030 + 5427
than, at last you add,
= 10457

Using algebraic logic, the answer would be 412857 but you could put brackets around any group of numbers and get a different answer every time.

No!!!! .
56 x 90 - 10 + 67 x 81
Since you did not place parentheses, I will do multiplications first
5040 - 10 + 5427 = 10457

56 x 90 - 10 + 67 x 81
= 5040 - 10 + 5427
= 5030 + 5427
= 10457

You could do with some brackets.


56 x 90 - 10 + 67 x 81 = 10457

You should use Bidmas when you are working out sums like this.

B rackets
I ndices
D ivision
M ultiplication
A ddition
S ubtraction

If you do it in that order it will be right.