如題，我想問個通項係咩
仲有點樣計，thx!!
1^2+2^2+3^2+...+n^2
2008-12-07 4:24 am
回答 (2)
2008-12-07 10:31 pm
✔ 最佳答案
1^2+2^2+3^2+...+n^2n
=Σ k^2
k=1
通項=k^2
2008-12-07 6:57 am
通項 = i^2.
The sum of the first n square numbers is equal to
n(n+1)(2n+1)/6
The sum of the first n square numbers is equal to
n(n+1)(2n+1)/6
收錄日期: 2021-04-13 16:17:54
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081206000051KK01542