Derivatives of Trigonometric Function

Diffence both sides w.r.s to x

2xcosy+x^2(-siny)y'+2cos2yy'=xy'+y

2xcosy+=xy'+x^2sinyy'-2cos2yy'

=y'(x+x^2siny-2cos2y)

y'=2xcosy/(x+x^2siny-2cos2y)

It is related to amath.


Hope I can help you.

diff. both sides w.r.s to x
2xcosy+x^2(-siny)y'+2cos2yy'=xy'+y
2xcosy+=xy'+x^2sinyy'-2cos2yy'
=y'(x+x^2siny-2cos2y)
y'=2xcosy/(x+x^2siny-2cos2y)
i think it is related to amath.....about chain rule...

2008-12-08 02:03:25 補充：
w.r.t. x .....SOR

2008-12-22 16:56:03 補充：
抄人!!!!
diff. = diffence 真好笑
應該是 differentiate
w.r.s. ?
另一個回答者都話講錯 都要照copy
應該是w.r.t. = with respect to!!!
抄人也可成為最佳解答?
他根本就不懂!!