Solve using the quadratic formula x^2 -2x=15x-10?

Subtract 15x - 10 from both sides.
x² - 2x - 15x + 10 = 15x - 10 - 15x + 10
x² - 17x + 10 = 0

Given: ax² + bx + c = 0
Quadratic Formula: x = [-b ± √(b² - 4ac)] / 2a

Given: x² - 17x + 10 = 0
Means: a = 1, b = -17, c = 10

x = [-b ± √(b² - 4ac)] / 2a
x = [-(-17) ± √((-17)² - 4(1)(10))] / 2(1)
x = [17 ± √(289 + -40)] / 2
x = [17 ± √249] / 2

x² - 2x = 15x - 10
x² - 17x = - 10
x² - 17/2x = - 10 + (- 17/2)²
x² - 17/2x = - 40/4 + 289/4
(x - 17/2)² = 249/4
x - 8.5 = 7.8898669

x = 7.8898669 + 8.5, x = 16.389867
x = - 7.8898669 + 8.5, x = 0.6101331

Answer: x = 16.389867, 0.6101331

Proof (x = 16.389867):
16.389867² - 2(16.389867) = 15(16.389867) - 10
268.6277 - 32.779732 = 245.84799 - 10
235.848 = 235.848

Proof (x = 0.6101331):
0.6101331² - 2(0.6101331) = 15(0.6101331) - 10
0.3722623 - 1.2202662 = 9.1519965 - 10
0.848= 0.848

x^2 - 2x = 15x - 10
x^2 - 2x - 15x + 10 = 0
x^2 - 17x + 10 = 0
x = [-b ±√(b^2 - 4ac)]/2a

a = 1
b = -17
c = 10

x = [17 ±√(289 - 40)]/2
x = [17 ±√249]/2

∴ x = [17 ±√249]/2

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x² - 17x + 10 = 0
x = [ 17 ± √ (289 - 40 ) ] / 2
x = [ 17 ± √ (249) ] / 2

x^2-2x=15x-10
x^2-17x+10=0

a=1 b=-17 c=10

-(-17)+/- sqrt -17^2-4(1)(10)/2
17 +/- sqrt 289 -40/2
17 +/- sqrt 249/2

1x^2-17x+10=0
a=1;b=[-17];c=10
x=[[-b]*sqr[b^2-4ac]]/2a
two answers
x1=16.389867
x2=0.61013308

x^2 - 2x = 15x - 10
x^2 - 17x + 10 = 0

a = 1, b = -17, c = 10
x = [-b +/- sqrt(b^2 - 4ac)] / (2a)
x = [17 +/- sqrt(17^2 - 4(1)(10)] / (2*1)
x = [17 +/- sqrt(259)] / 2