evaluate: [(3/4)^-2*(1/4)^4]-2?
2008-12-04 3:15 pm
How would I approach this question, I cannot for the life of me remeber how to work out rational numbers to negative exponents?! aarrgghh! PLEASE HELP!
回答 (6)
2008-12-04 3:33 pm
✔ 最佳答案
[ (16/9) (1/256) ] ^(-2)256² (9²)
------------
16²
(16^4) ( 9² )
---------------
16²
16² 9²
20736
2008-12-04 3:46 pm
just go to either myalgebra.com or easycalculation.com both sites will answer your math roblems and even explain the step by step process of it too.
2008-12-04 4:28 pm
id go were austin said to go i use myalgebra all the time
2008-12-04 3:46 pm
(3/4)^-2 = [(3/4)²]^-1 = (9/16)^-1 = 1/(9/16) = 16/9
(1/4)^4 = 1/(4)^4 = 1/256.
Now, multiply the two results above, and then square that result and take its reciprocal. When you do that, you get this:
{[(16/9)(1/256)]²}^-1 = {[(1/9)(1/16)]²}^-1 = [(1/144)²]^-1 = (1/20736)^-1 = 20736
(1/4)^4 = 1/(4)^4 = 1/256.
Now, multiply the two results above, and then square that result and take its reciprocal. When you do that, you get this:
{[(16/9)(1/256)]²}^-1 = {[(1/9)(1/16)]²}^-1 = [(1/144)²]^-1 = (1/20736)^-1 = 20736
2008-12-04 3:30 pm
[(3/4)^-2 x (1/4)^4]^-2
= (3/4)^(-2 x -2) x (1/4)^(4 * -2)
= (3/4)^4 x (1/4)^-8
= (3/4)^4 x 1/(1/4)^8
= (3/4)^4 x (4/1)^8
= (3/4)^4 x 4^8
= 3^4/4^4 x 4^8
= 3^4 x 4^(8 - 4)
= 3^4 x 4^4
= (3 x 4)^4
= 12^4 (20736)
= (3/4)^(-2 x -2) x (1/4)^(4 * -2)
= (3/4)^4 x (1/4)^-8
= (3/4)^4 x 1/(1/4)^8
= (3/4)^4 x (4/1)^8
= (3/4)^4 x 4^8
= 3^4/4^4 x 4^8
= 3^4 x 4^(8 - 4)
= 3^4 x 4^4
= (3 x 4)^4
= 12^4 (20736)
2008-12-04 3:22 pm
The answer is 2
收錄日期: 2021-05-01 11:38:12
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081204071516AAXkgLl