Physics Mechanics

2008-12-05 6:39 am
A sled of mass 10kg with a parcel of mass 2 kg on it is initially at rest on a slope which makes an angle of 25 degree to the horizontal. The Sled is now pulled by a rope parallel to the slope
Neglect the mass of the rope and the friction between the slope and the sled

Suppose the max. Friction between the parcel and the sled before the parcel slides is 25N. Without the slippery of the parcel, what is the max. tension in the rope
更新1:

The ans is 99.3 N, But I dun know how to calculate it~

回答 (2)

2008-12-11 4:54 am
✔ 最佳答案

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2008-12-05 7:33 am
T+f=mgsin25
T+25=12*10*sin25
T=25.7N

mgsin25 is a force which reduce the tension of the rope.f(friction) is a force which increase the tension of the rope.


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