dispersion

2008-12-05 4:36 am
k-7,k-3,k.k+4 and k+6,find their standard deviation
更新1:

i don't understand why mean is k?

回答 (2)

2008-12-05 5:49 am
✔ 最佳答案
Mean = 5k/5 = k.
so [k - 7 - k}^2 = 49
[k - 3 - k]^2 = 9
[k - k]^2 = 0
[k + 4 - k]^2 = 16
[k + 6 - k]^2 = 36
sum = 110
sum/5 = 110/5 = 22
S.D. = sqrt(22).

2008-12-05 21:36:06 補充:
Mean = average = [(k-7) + (k-3) + k + (k+4) + (k+6)]/5 = 5k/5 = k.
2008-12-05 6:38 am
E(X) = k

E(X ^ 2) = (k ^ 2) + 22

Var (X) = E(X ^ 2) - {[E(X)] ^ 2} = 22

standard deviation = sqrt (22)


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