Would it be 1/3^2 = 1/9?
Does this mean that lets say 3^-3 is 1/3^3 = 1/ 27, and so on?
更新1:
What if it was . . . lets say 3^-2x Where does the x go?
log3(N)= -2, than N = ?
2008-12-03 9:50 am
So wouldn't it be 3^ -2 .....
Would it be 1/3^2 = 1/9?
Does this mean that lets say 3^-3 is 1/3^3 = 1/ 27, and so on?
Would it be 1/3^2 = 1/9?
Does this mean that lets say 3^-3 is 1/3^3 = 1/ 27, and so on?
回答 (6)
2008-12-03 9:57 am
✔ 最佳答案
N = 3^(-2)N = 1/3^2
N = 1/9
Your understanding of the process is correct.
<<Does this mean that lets say 3^-3 is 1/3^3 = 1/ 27, and so on?>>
YES ... it is.
Hope this helps.
2008-12-03 6:17 pm
log3(N) = -2
N = 3^(-2)
N = 1/9
Answer: N = 1/9
N = 3^(-2)
N = 1/9
Answer: N = 1/9
2008-12-03 6:07 pm
Yes, u r correct.
log ~base 3~ (3^-2) = -2 { log ~base 3~ 3 } = -2 (1) = -2.
That is, N = 3^(-2) = 1 / 3^2 = 1/9
Yes, 3^-3 = 1/3^3 = 1/27
3^-4 = 1/3^4 = 1/81, so on...
Where do u have x here?
Why do u take N as 3^-2x? This is wrong...
N is 3^-2. Not 3^-2x.
log ~base 3~ (3^-2) = -2 { log ~base 3~ 3 } = -2 (1) = -2.
That is, N = 3^(-2) = 1 / 3^2 = 1/9
Yes, 3^-3 = 1/3^3 = 1/27
3^-4 = 1/3^4 = 1/81, so on...
Where do u have x here?
Why do u take N as 3^-2x? This is wrong...
N is 3^-2. Not 3^-2x.
2008-12-03 6:06 pm
log3(N) = -2,
(10)^(-2) = 3.N
1 / (10)^2 = 3N
N = 1 / 300. Answer.
(10)^(-2) = 3.N
1 / (10)^2 = 3N
N = 1 / 300. Answer.
參考: Any math book
2008-12-03 6:04 pm
log_3(n) = -2
3^(-2) = n
n = 1/3^2
n = 1/9
3^(-2) = n
n = 1/3^2
n = 1/9
2008-12-03 6:00 pm
Let log be log to base 3
log N = - 2
N = 3^(-2)
N = 1 / 9 (agreed !)
Also 3^(-3) = 1 / 3³ = 1/27 (agreed !)
Also 3^(-2x) = 1 / 3^(2x)
Also if 3^(-2) x = x / 3² = x / 9
log N = - 2
N = 3^(-2)
N = 1 / 9 (agreed !)
Also 3^(-3) = 1 / 3³ = 1/27 (agreed !)
Also 3^(-2x) = 1 / 3^(2x)
Also if 3^(-2) x = x / 3² = x / 9
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