solve by factoring: 3x^2 + 4x - 10 = 0?

3x^2 + 4x - 10 = 0 (cannot be factored)
x = [-b ±√(b^2 - 4ac)]/2a (quadratic equation)

a = 3
b = 4
c = -10

x = [-4 ±√(16 + 120)]/6
x = [-4 ±√136]/6
x = [-4 ±√(2^2 * 2 * 17)]/6
x = [-4 ±2√(2 * 17)]/6
x = [-4 ±2√34]/6
x = [-2 ±√34]/3

∴ x = [-2 ±√34]/3

x = [ - 4 ± √ (16 + 120 ) ] / 6

x = [ - 4 ± √ (136) ] / 6

x = [ - 4 ± 2 √34 ] / 6

Does not factor.

hello u mean 3x square+4x-10=0

it is not factorable