5[12 - (6 - 3a) - 2a] = 2(1 - a)?
回答 (8)
2008-12-02 2:44 pm
✔ 最佳答案
5[12 - (6 - 3a) - 2a] = 2(1 - a)?5[12-6+3a-2a]=2-2a
5[6+a]=2-2a
30+5a=2-2a
5a+2a=2-30
7a=-28
a=-4
I hope this help...
2008-12-02 3:12 pm
5[12 - (6 - 3a) - 2a] = 2(1 - a)
5[12 - 6 + 3a - 2a] = 2*1 - 2*a
5[6 + a] = 2 - 2a
30 + 5a = 2 - 2a
2a + 5a = 2 - 30
7a = -28
a = -28/7
a = -4
5[12 - 6 + 3a - 2a] = 2*1 - 2*a
5[6 + a] = 2 - 2a
30 + 5a = 2 - 2a
2a + 5a = 2 - 30
7a = -28
a = -28/7
a = -4
2008-12-02 2:54 pm
A question well presented.
5 [ 6 + 3a - 2a ] = 2 - 2a
30 + 5a = 2 - 2a
7a = - 28
a = - 4
5 [ 6 + 3a - 2a ] = 2 - 2a
30 + 5a = 2 - 2a
7a = - 28
a = - 4
2008-12-02 2:48 pm
a=4
2008-12-02 2:47 pm
First, expand the brackets:
5[12 - 6 + 3a -2a] = 2(1-a)
Then, cancel on the left:
5[6 + a] = 2(1-a)
And multiply out:
30 + 5a = 2 - 2a
Move the a's to the left, numbers to the right:
7a = -28
and divide numbers by multiples of 'a':
a = -28/7 = -4
Check by putting it all back together:
5[12 - (6 - 3*-4) - 2*-4] = 5 * 2 = 10
2(1- -4) = 2 * 5 = 10
5[12 - 6 + 3a -2a] = 2(1-a)
Then, cancel on the left:
5[6 + a] = 2(1-a)
And multiply out:
30 + 5a = 2 - 2a
Move the a's to the left, numbers to the right:
7a = -28
and divide numbers by multiples of 'a':
a = -28/7 = -4
Check by putting it all back together:
5[12 - (6 - 3*-4) - 2*-4] = 5 * 2 = 10
2(1- -4) = 2 * 5 = 10
2008-12-02 2:40 pm
5[12 - (6 - 3a) - 2a] = 2(1 - a)
5(12 - 6 + 3a - 2a) = 2 - 2a
5(6 + a) = 2 - 2a
30 + 5a = 2 - 2a
7a = -28
a = -4
Regards.
Volkan (Turkey)
5(12 - 6 + 3a - 2a) = 2 - 2a
5(6 + a) = 2 - 2a
30 + 5a = 2 - 2a
7a = -28
a = -4
Regards.
Volkan (Turkey)
2008-12-02 2:39 pm
5[6+a] = 2 -2a
30 -2 = -7a
a = -4
30 -2 = -7a
a = -4
2008-12-02 2:39 pm
a= -4
收錄日期: 2021-05-01 11:35:04
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081202063341AAmcbYy