a) A manufacturer claims that the life of his batteries is normally distributed with mean = 60 hours and standard deviation 30 minutes. find the value of t if 2.5% of the batteries last more than t hours.
b) The interest for a loan of 1 year is 2.5% per month. the loan is to be repaid in one-off in full at the end of the loan period. calculate the actual interest rate per annum.
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2008-12-02 2:19 am
回答 (2)
2008-12-02 7:04 am
✔ 最佳答案
a)Pr (t > to) = 2.5%
(to - 60hrs) / 30 mins = 1.96
to = 60.98hrs
b)
P x [(1 + 2.5%) ^ 12] = P x (1 + i)
i = (1.025 ^ 12) - 1 = 0.3449 = 34.49%
2008-12-02 2:25 am
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