What is the waiting-to-be-factored form of 4n^2+30n+30?

2008-11-29 4:01 pm

回答 (5)

2008-11-29 4:04 pm
✔ 最佳答案
2(2n^2 + 15n + 15)
2008-11-30 2:14 am
4n^2 + 30n + 30
= 2(2n^2 + 15n + 15n)
2008-11-30 12:23 am
4(n+1.188262309)(n+6.311737692)=
=(4n+7.5)(n+6.311737692)
2008-11-30 12:23 am
4n^2+30n+30
= 2 (2n^2 + 15n + 15)
= 4 [n+ ((15-√105)/4)][n + ((15 +√105)/4 ]
where (- 15 ± √105)/4 are roots of the equation 2n^2 + 15n + 15 = 0
2008-11-30 12:08 am
4n^2+30n+30

first factor out a 2

2 (2n^2 + 15n + 15)

That's as far as you can take it, the Trinomial part cannot be factored so you need to use the quadratic formula to find the factors


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