Sove by the substitution method?

4m + n = 17
n = 17 - 4m ---------(1)

Substitute (1) into
m - 3n = 17
m - 3 (17 - 4m) = 17
m - 51 + 12m = 17
13m = 68
m = 68/13
m = 5 (3/13)----------(2)

Substitute (2) into (1)
n = 17 - 4m
n = 17 - 4 (68/13)
n = 17 - 272/13
n = -51/13
n = -3 (12/13)


OR


m - 3n = 17
m = 17 + 3n----------(1)

Substitute (1) into
4m + n = 17
4 (17 + 3n) + n = 17
68 + 12n + n = 17
68 + 13n = 17
13n = -51
n = -51/13
n = -3 (12/13)-----------(2)

Substitute (2) into (1)
m = 17 + 3n
m = 17 + (-51/13)
m = 68/13
m = 5 (3/13)

from 2 nd equ .
m=3n+17 ...................................(3)
now put in 1st equ.
4(3n+17)+n=17
13n=-51
n=-51/13 now put it to the 3 rd.
m=3(-51/13)+17
m=68/13

4m + n = 17
m - 3n = 17

m - 3n = 17
m = 17 + 3n

4m + n = 17
4(17 + 3n) + n = 17
68 + 12n + n = 17
13n = 17 - 68
13n = -51
n = -51/13

m - 3n = 17
m - 3(-51/13) = 17
m + 153/13 = 17
m = 17 - 153/13
m = 221/13 - 153/13
m = 68/13

∴ m = 68/13 , n = -51/13

4m + n = 17..........(1)
m - 3n = 17...........(2)

n = 17 - 4m...........From (1). Substitute this value in (2)
m - 51 + 12m = 17
13m = 68
m = 68/13
n = 17 - 272/13 = - 51/13

equation 2 can be rearranged to:
m = 17 + 3n
and you can substitute that into the first equation
4(17 + 3n) + n = 17
68 + 12n + n = 17
13n = -51
n = -51/13

and substitute that value:
m = 17 - 3*51/13
whatever that is

4m+n=17 (1)
m-3n=17 (2)

using (2)
m-3n=17
m=17+3n (3)

Substitue (3) into (1)
4m+n=17
4(17+3n)=17
68+12n=17
12n=-51
n= -12/51 (4)

Substitue (4) into (3)
m=17+3n
m=17+3(-12/51)
m=17-36/51
m= 16 15/51