Kitty has some cherries.Betty has 6 more cherries than Kitty.Later,each of them eats 12 cherries.Then the number of cherries that Kitty has is two-thirds that of Betty has.
a) how many cherries does each of them have originally?
b) how many cherries does each of them have mow?
c)later,they eat y more cherries .if the number of cherries that Betty has is twice that of Kitty has,fine the value of y.
F.I math
2008-11-27 4:31 am
回答 (4)
2008-11-27 4:47 am
✔ 最佳答案
Let Kitty has K cherries, Betty has B cherriesB=K+6
(K-12) = 2/3* (B-12) = 2B/3-8 or K=2B/3 +4
Therefore B = 2B/3 + 4 +6 = 2B/3 +10
1/3B=10 or B=30
K=24
a) Kitty has 24 cherries; Betty has 30 cherries
b) Kitty has 12 cherries; Betty has 18 cherries now
c)
18-y=2*(12-y)=24-2y
y=6
2008-11-27 7:02 am
a. Kitty:24 Betty:30
b.Kitty:12 Betty:18
c. y=6
b.Kitty:12 Betty:18
c. y=6
2008-11-27 5:00 am
a)Let a be kitty originally have,b be betty originally have.
a-12=2(a+6-12)/3
a=24
b)(24-12)+(24+6-12)
=30
c)a-12-y=(a+6-12-y)/2
24-12-y=(24+6-12-y)/2
y=6
a-12=2(a+6-12)/3
a=24
b)(24-12)+(24+6-12)
=30
c)a-12-y=(a+6-12-y)/2
24-12-y=(24+6-12-y)/2
y=6
2008-11-27 4:52 am
Let Kitty has X cherries, then Betty has X+6 cherries.
After they both eat 12 cherries, Kitty has X-12 and Betty has X -6
X-12 = 2/3 ( X-6)
3X-36 = 2X -12
X= 24
a) Kitty has 24 and Betty has 30 originally.
b) Kitty has 12 and Betty has 18 now.
c) 2 ( 12-y) = 18 -y
24 -2y = 18 -y
y = 6
After they both eat 12 cherries, Kitty has X-12 and Betty has X -6
X-12 = 2/3 ( X-6)
3X-36 = 2X -12
X= 24
a) Kitty has 24 and Betty has 30 originally.
b) Kitty has 12 and Betty has 18 now.
c) 2 ( 12-y) = 18 -y
24 -2y = 18 -y
y = 6
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