how would you solve 3t/(t+2) = (t-2)/6t? ?

18t^2=t^2-4

17t^2=-4

t^2= - 4/17

t is not real

18 t ² = (t - 2)(t + 2)
18 t ² = t ² - 4
17 t ² = - 4
17 t ² = 4 i ²
t = ± 2 i / √17

3t/(t + 2) = (t - 2)/6t
3t = (t - 2)(t + 2)/6t
3t(6t) = t*t - 2*t + 2*t - 2*2
18t^2 = t^2 - 2t + 2t - 4
18t^2 = t^2 - 4
18t^2 - t^2 = -4
17t^2 = -4
t^2 = -4/17
t = ±√(-4/17)
t = ±√(4/17i)
t = ±2i√(1/17)

3t/(t+2) = (t-2)/6t
just cross multiply
3t x 6t = t^2 - 4
18t^2 = -4
t^2 = under root of -4/17 which will be equal to + or - 2i/root 17

3t/(t+2)=(t-2)/6t

3t*6t=(t+2)(t-2) (Cross Multiplication)

18t^2=t^2-4

17t^2=-4

t^2=(-4/17)

t= root of (-4/17)

t= root of <-1*(4/17)>

t=(2i/root of 17)

cross multiply the equation

u'll get 3t (6t) = (t+2) (t-2)

expand the equation

u'll get 18t^2 = t^2 - 4

rearrange..

17t ^ 2 = -4

t^2 = - 4 / 17

T = -2 / Square root 17

T = -2 square root 17 / 17

18 t ² = (t - 2)(t + 2)
18 t ² = t ² - 4
17 t ² = - 4
17 t ² = 4 i ²
t = ± 2 i / √17