急問F.1math,,percentages-5條(列式)~!!

2008-11-26 4:23 am
1 ) Judy wants to borrow $1000000 from a bank for 10 years . Bank A charges simple interest at an interest rate of 5% p.a. and Bank B charges simple interest at an interest rate of 4.5% p.a. If Judy borrows from Bank B , how much interest would she be playing less than from Bank A ?
更新1:

2) Clement deposits $80000 in a bank at an interest rate of 10% p.a. , and he deposits $60000 in another bank at an interest rate of 9% p.a. Find the total amount that he will get after 5 years .

更新2:

3) Simple interest is given at an interest rate of 2.4% p.a. for an investment of $20000 . How long will it take the amount to become $22160 ?

更新3:

4 ) Shrley deposits $ 6000 in a bank at an interest rate of R% p.a. If the interest rate changes to 5.5% p.a. , Shrley will get $180 more as the simple interest two years later . Find the value of R .

更新4:

5 ) Find the principal that will amount to $13156 after 73 days if simple interest is calculated at an interest rate of 6% p.a. ( Take 1 year = 365 days . )

回答 (2)

2008-11-27 2:39 am
✔ 最佳答案
1)
[1000000x 5%x10]-[1000000x 4.5%x10]

=500000-450000

=50000

or

1)
1000000x[5%-4.5%]x10

=50000


2)
80000x[1+10%]x5+60000x[1+9%]x5

=440000+327000

=767000

3)
Let t be the time.

20000x2.4%xt+20000=22160

480t=2160

t=4.5

4)

(6000x5.5%x1)-(6000xR%x1)=180

330-6000*R%*1=180

- 6000xR%=-150

R%=0.025

R/100=0.025

R=2.5

5)

Let p be the principal

px73/365x6%+p=13156

1.012p=13156

p=13000

Hope I can help you.
參考: my maths knowledge
2008-11-26 6:01 am
1)[1000000* 5%*10]-[1000000* 4.5%*10]
=500000-450000
=50000

OR

1) 1000000*[5%-4.5%]*10
=50000


2) 80000*[1+10%]*5+60000*[1+9%]*5
=440000+327000
=767000

3)
Let t be the time.
20000*2.4%*t+20000=22160
480t=2160
t=4.5

4)
(6000*5.5%*1)-(6000*R%*1)=180
330-6000*R%*1=180
- 6000*R%=-150
R%=0.025
R/100=0.025
R=2.5

5)
Let p be the principal
p*73/365*6%+p=13156
1.012p=13156
p=13000

2008-11-25 22:02:19 補充:
主要背戈幾條式就做到..


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