Q1: (-2x^-2y3)^-2
Q2: (-3y^-2)^2
(Please type the answers and steps!)
Please solve this problem as soon as possible! (20 pts)
2008-11-26 4:04 am
回答 (5)
2008-11-26 6:03 am
✔ 最佳答案
The answer is as follows:圖片參考：http://i277.photobucket.com/albums/kk75/uncle_michael/20081125_mat_1.jpg?t=1227621776
2008-12-05 4:15 am
Q1: (-2x^-2y3)^-2
(-2x^-2y3)^-2
=(-2x-2y3)-2
=(1/-2x2y3)-2
=(1/-2x6y)-2
=1-2/-2x-36y
=-2x36y/12
=-2x36y
Q2: (-3y^-2)^2
(-3y^-2)^2
=(-3y-2)2
=(1/-3y2)2
=1/9y4
(-2x^-2y3)^-2
=(-2x-2y3)-2
=(1/-2x2y3)-2
=(1/-2x6y)-2
=1-2/-2x-36y
=-2x36y/12
=-2x36y
Q2: (-3y^-2)^2
(-3y^-2)^2
=(-3y-2)2
=(1/-3y2)2
=1/9y4
2008-11-26 6:27 am
Uncle Michael果然係專家，答得好好ｂｏ；）
2008-11-26 6:09 am
Q1: (-2x^-2y3)^-2
(-2x^-2y3)^-2
=(-2x-2y3)-2
=(1/-2x2y3)-2
=(1/-2x6y)-2
=1-2/-2x-36y
=-2x36y/12
=-2x36y
Q2: (-3y^-2)^2
(-3y^-2)^2
=(-3y-2)2
=(1/-3y2)2
=1/9y4
(-2x^-2y3)^-2
=(-2x-2y3)-2
=(1/-2x2y3)-2
=(1/-2x6y)-2
=1-2/-2x-36y
=-2x36y/12
=-2x36y
Q2: (-3y^-2)^2
(-3y^-2)^2
=(-3y-2)2
=(1/-3y2)2
=1/9y4
2008-11-26 4:39 am
sorry i just know Q2
Q2: (-3y^-2)^2
(-3y^-2)^2
=(-3y)^(-2*2)
=(-3y)^(-4)
=1/[(3^4)(y^4)]
=1/81y^4
Q2: (-3y^-2)^2
(-3y^-2)^2
=(-3y)^(-2*2)
=(-3y)^(-4)
=1/[(3^4)(y^4)]
=1/81y^4
參考: me
收錄日期: 2021-04-24 09:53:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081125000051KK01593