A wire of 53 cm long is cut into parts . The longer wire is bent to form an equilateral triangle . The shorter one is bent to form a square is 6 cm shorter than that of the triangle, find the respective lengths of the longer and shorter wire
please explain to me and teacher me how to do !!!
Please!!thx
中一英文代數
2008-11-25 12:02 am
回答 (2)
2008-11-25 2:23 am
✔ 最佳答案
Let length of the longer wire = x.so length of the shorter wire = 53 - x.
Side of the equilateral triangle = x/3.
Side of the square = (53-x)/4.
Since side of square is 6cm shorter than the triangle, therefore,
x/3 - 6 = (53-x)/4
4x - 72 = 3(53 - x)
4x - 72 = 159 - 3x
7x = 231
x = 231/7 = 33 = length of longer wire.
53 - 33 = 20 = length of shorter wire.
2008-11-25 12:44 am
Let 3x cm be the length of longer wire,
therefore the length of shorter wire is 4(x-6) cm
4(x-6) + 3x = 53
4x-24+3x = 53
7x = 77
x = 11
therefore, the length of longer and shorter wire are 33 cm and 20 cm
therefore the length of shorter wire is 4(x-6) cm
4(x-6) + 3x = 53
4x-24+3x = 53
7x = 77
x = 11
therefore, the length of longer and shorter wire are 33 cm and 20 cm
參考: me
收錄日期: 2021-04-23 23:16:04
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081124000051KK00867