a= 1 real solution
b= 2 real solutions
c= 2 imaginary solutions
Determine the nature of the solution of the equation: x^2-1= 0?
2008-11-23 10:38 am
回答 (3)
2008-11-23 10:40 am
✔ 最佳答案
ax² + bx + c = 0a = 1
b = 0
c = -1
b²-4ac
= 0 + 4
= 4 > 0
Two real and distinct solutions
2008-11-24 12:00 am
x^2 - 1 = 0
x^2 = 1
x = 屉1
x = ±1
(answer b)
x^2 = 1
x = 屉1
x = ±1
(answer b)
2008-11-23 7:05 pm
b= 2 real solutions
The solutions are x = -1 and x = 1
The solutions are x = -1 and x = 1
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