Math help please, solve for x?

This equation cannot be solved by factor method. So use the formula:
-b±√b²-4ac/2a
Here, a = 4, b=4, c = -7
On substitution in the formula,
Roots are[x=]: -1±√8/2

4x*2+4x=7
8x+4x=7
12x=7
x=7/12

4x^2 + 4x = 7
4x^2 + 4x - 7 = 0
x = [-b ±√(b^2 - 4ac)]/2a

a = 4
b = 4
c = -7

x = [-4 ±√(16 + 112)]/8
x = [-4 ±√128]/8
x = [-4 ±√(2^6 * 2)]/8
x = [-4 ±2^3√2]/8
x = [-4 ±8√2]/8
x = -1/2 ±√2

∴ x = -1/2 ±√2

(-b+/- sqt (b^2 -4ac))/2a,

Here a=4,b=4,c=-7
Subtituting these values
-4+/-sqt(4^2 -4*4*-7)/2*4
-4+/-sqt(16+112)/8
-4+/-sqt(128)/8
-4+/-sqt(64*2)/8
-4+/-8sqt2/8
-4(1+/-2sqt2)/8
-1+/-2sqt2/2
-1+2sqt2/2 or -1-2sqt2/2

the equation is a quadratic equation. There are 3 ways to solve a quadratic eq.: completing the square, factoring and the easiest and fastest way, quadratic formula. Assume we chose quadratic formula in this eq. but first we cannot use quadratic formula if it isn't arrange in the standard form: ax^2 + bx + c = 0. so, the first thing you do is to change it to the standard form. 4x^2 +4x - 7 = 0. then use QF. I hope you haven't forgot your QF.

in the end, you'll have
x = 0.91, x =-1.91
the answer is in a radical form. i use a calculator so now it's in decimal form

hope a gave you the right answer and that this would help.

-1/2 + √2 and 1/2 - √2

Make equation into a quadratic equation by sub 7 both sides

4x² + 4x = 7 sub 7 from both sides
4x² + 4x - 7 = 0

Use the Quadratic Equation at this site and work out the problem.

http://www.1728.com/quadratc.htm

4x^2+4x=7
4x^2+4x-7=0

using the quadratic formula....
(-b+/- sqt (b^2 -4ac))/2a

-4+/- sqt (16+56)
------------------------
8

-4+/- sqt (72)
------------------
8

x= 0.561 and -1.561

4x^2+4x=7
so
4x^2+4x-7 = 0
so use the quadratic formula to find values for x, where a=4, b=4, c=-7.

subtract the 7 first then use the quadratic equation:

http://en.wikipedia.org/wiki/Quadratic_equation

You can also graph it (after subtracting the 7) and look to see where the equation crosses the x-axis (i.e. where y=0).