know that f(1)=3, f'(1)= -4 及g(x)=(x^2)(f(x))
find g'(1)
math derivative question(3)
2008-11-20 12:14 am
回答 (1)
2008-11-20 12:24 am
✔ 最佳答案
g(x)=(x^2)(f(x))g'(x)=(2x)(f(x))+(x^2)(f'(x))
g'(1)=(2)(f(1))+(f'(1))=2*3+(-4)=2
收錄日期: 2021-04-25 16:58:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081119000051KK00751