5條[中一]方程數學題 !!功課...急呀__!請入 ~~10點 ))

2008-11-19 2:43 am
唔該"要詳細過程呀!!

1) 2(m-1) / 7 + 2 = 5m / 7

2) 3[4m - 5(m-1)] = 1 - 2m

3) 2x +3 / 8 -3 = 3 - 2x / 6 - 4

4) z-3 / 2 +5 = 2z + 1 / 3 - z +3 / 4

5) 2(2p + 1 + p +3 ) = 38



P.S :: / = 除 !!

唔該快D幫我呀 !!
更新1:

3) 2x +3 3- 2x --------- - 3 = ---------- -4 8 6 4) z - 3 2z + 1 z + 3 ----- + 5 = --------- - --------- 5 3 4

回答 (3)

2008-11-19 3:03 am
✔ 最佳答案
1)
2(m-1) / 7 + 2 = 5m / 7
2(m-1) + 14 = 5m....................一齊乘7
2m-2 + 14 = 5m
2m +12 = 5m
12 = 3m
m=4

2)
3[4m - 5(m-1)] = 1 - 2m
3(4m - 5m +1) = 1 - 2m
3( - m +1) = 1 - 2m
- 3m +3 = 1 - 2m
2 = m
m =2

3)
2x +3 / 8 -3 = 3 - 2x / 6 - 4
2x +3 / 8 -3 = 3 - 2x / 6 - 4
48x +9 -72 = 72 -8x -96.....................一齊乘24
48x -63 = -8x -24
56x = 39
x=39/56

4)
z-3 / 2 +5 = 2z + 1 / 3 - z +3 / 4
6(z-3) +60 = 24z +4 -12z +9..............一齊乘12
6z -18 +60 = 12z +13
6z +42 = 12z +13
6z=29
z=29/6

5)
2(2p + 1 + p +3 ) = 38
2( 3p +4 ) = 38
3p +4 = 19
3p=15
p=5


以上題目 全按照"先乘除,後加減" ,這鐵則運算

2008-11-18 19:06:21 補充:
2)
3[4m - 5(m-1)] = 1 - 2m
3(4m - 5m +5) = 1 - 2m
3( - m +5) = 1 - 2m
- 3m +15 = 1 - 2m
14 = m
m = 14
參考: 會考數學拿c既人~
2008-11-19 3:13 am
1) 2(m-1) / 7+2 = 5m / 7
7[2(m-1) / 7 +2] = 7(5m/7)
2(m-1)+14 = 5m
2m-2+14 = 5m
2m+12 = 5m
12 = 5m-2m
12 = 3m
m = 12/3
m = 4

2) 3[4m - 5(m-1)] = 1 - 2m
3(4m - 5m + 5) = 1 - 2m
12m - 15m + 15 = 1-2m
15-3m = 1-2m
15-1 = 3m-2m
m = 14

3), 4) 我不太肯定你的括號是不是對的
你是否肯定題目是2x + (3/8) - 3 = 3 - (2x/6) - 4和
z - (3/2) + 5 = 2z + (1/3) - z + (3/4)???

待會再補充.


5) 2(2p + 1 + p +3 ) = 38
2p + 1 + p + 3 = 19
3p = 19-1-3
3p = 15
p = 5
參考: MYSELF
2008-11-19 3:02 am
I can help u 2 of them!!!~
2) 3[4m - 5(m-1)] = 1 - 2m
12m-15m+3=1-2m
2=1m
m=2

5) 2(2p + 1 + p +3 ) = 38
4p+2+2p+6=38
6p+8=38
6p=30
p=5

2008-11-18 19:08:19 補充:
上面001個人 no.5 is wrong!!!!

the correct answer is 5!!!!


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