1. a^2 + 8a + 16 - m^2
2. 1 - a^2 -2ak - k^2
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2008-11-19 2:01 am
Factorize the following expressions.
1. a^2 + 8a + 16 - m^2
2. 1 - a^2 -2ak - k^2
1. a^2 + 8a + 16 - m^2
2. 1 - a^2 -2ak - k^2
回答 (2)
2008-11-19 2:13 am
✔ 最佳答案
1.a^2+8a+16-m^2=(a+4)^2-m^2
=(a+4+m)(a+4-m)
a^2-b^2=(a+b)(a-b)
2.1 - a^2 -2ak- k^2
=-( a^2+2ak+k^2-1)
=-[(a+k)^2-1]
=-(a+k+1)(a+k-1)
參考: 我
2008-11-19 3:30 am
1.
a^2 + 8a + 16 - m^2
=a² + 8a + 16 - m²
=(a)²+2(a)(4)+(4)² -m²
=(a+4)² -m²....................................a²+2ab+b²=(a+b)²
=(a+4-m)(a+4+m).......................a²-b²=(a-b)(a+b)
2.
1 - a^2 -2ak - k^2
=1 - a² -2ak - k²
=1 -(a² +2ak + k²)
=1² -(a+k)²..........................a²+2ab+b²=(a+b)²
=(1+a+k)(1-a-k)..................a²-b²=(a-b)(a+b)
a^2 + 8a + 16 - m^2
=a² + 8a + 16 - m²
=(a)²+2(a)(4)+(4)² -m²
=(a+4)² -m²....................................a²+2ab+b²=(a+b)²
=(a+4-m)(a+4+m).......................a²-b²=(a-b)(a+b)
2.
1 - a^2 -2ak - k^2
=1 - a² -2ak - k²
=1 -(a² +2ak + k²)
=1² -(a+k)²..........................a²+2ab+b²=(a+b)²
=(1+a+k)(1-a-k)..................a²-b²=(a-b)(a+b)
參考: 會考數學拿c既人~
收錄日期: 2021-04-29 16:12:35
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