Can someone please help me with this algebra problem? (x-2)/3-(x+5)/6=(5x-2)/9 ?
回答 (5)
2008-11-16 2:43 pm
✔ 最佳答案
(x-2)/3 - (x+5)/6 = (5x-2)/9multiply by 18
6(x-2) - 3(x+5) = 2(5x-2)
6x – 12 – 3x – 15 – 10x + 4 = 0
–7x –23 = 0
x = –23/7
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2008-11-16 2:51 pm
2x-4-x-5/6=5x-2/9
x-9/6=5x-2/9
9x-81=30x-12
30x-9x=-81+12
21x=-69
x=-69/21=-27/3
x-9/6=5x-2/9
9x-81=30x-12
30x-9x=-81+12
21x=-69
x=-69/21=-27/3
2008-11-16 2:48 pm
(x-2)/3 - (x+5)/6 = (5x-2)/9
take the LCM on LHS
( 2(x-2) -1(x+5)) / 6 =(5x-2) / 9
(2x-4-x+5) / 6 = (5x-2) / 9
(x+1) / 6 = (5x-2) /9
by cross multiplication
9*(x+1) = 6*(5x-2)
9x+9 = 30x -12
9+12 = 30x-9x ,21 = 21x , x = 21/21 , x=1
take the LCM on LHS
( 2(x-2) -1(x+5)) / 6 =(5x-2) / 9
(2x-4-x+5) / 6 = (5x-2) / 9
(x+1) / 6 = (5x-2) /9
by cross multiplication
9*(x+1) = 6*(5x-2)
9x+9 = 30x -12
9+12 = 30x-9x ,21 = 21x , x = 21/21 , x=1
2008-11-16 2:45 pm
(x - 2)/3 - (x + 5)/6 = (5x - 2)/9
18[(x - 2)/3 - (x + 5)/6] = 18[(5x - 2)/9]
6(x - 2) - 3(x + 5) = 2(5x - 2)
6*x - 6*2 - 3*x - 3*5 = 2*5x - 2*2
6x - 12 - 3x - 15 = 10x - 4
6x - 3x - 10x = 12 - 4 + 15
-7x = 23
x = 23/-7
x = -23/7
18[(x - 2)/3 - (x + 5)/6] = 18[(5x - 2)/9]
6(x - 2) - 3(x + 5) = 2(5x - 2)
6*x - 6*2 - 3*x - 3*5 = 2*5x - 2*2
6x - 12 - 3x - 15 = 10x - 4
6x - 3x - 10x = 12 - 4 + 15
-7x = 23
x = 23/-7
x = -23/7
2008-11-16 2:42 pm
Multiply both sides by 18 getting:
6x-12 -3x-15 = 10x -4
-7x = -23
x = 23/7
6x-12 -3x-15 = 10x -4
-7x = -23
x = 23/7
收錄日期: 2021-05-01 11:31:55
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