Solve the following equations for X.?

2x + 3 = x + 9

-x from both sides

x + 3 = 9

- 3 from both sides

x = 6

its a balancing equation

to find the value of x you have to see how much is the difference

3 is a 3rd of 9, so the value for x is going to be 6

2x 6 + 3 is 15

6+ 9 is 15

2x - x = 9 - 3
x = 6

Transpose the terms containing the variable (i.e., x) to the left hand side and the constant terms 3 and 9 to the right.
2x-x = 9-3
x=6

2x + 3 = x + 9
2x - x = -3 + 9
x = 6

The logical way is to move the Xs to one side and the numbers to the other. That is what all the examples are doing.
When you move a value from one side to the other you need to change its sign, that means + becomes - and - becomes +.

2x -x = x
and 9-3 =6
as there is only one x the answer is x = 6.


For the equation 3x -3 = x + 9
3x -x = 2x
9+3 = 12
therefore 2x = 12
and x = [12 divide by 2] 6

Just collect all the x's on the left side and all the numerical values on the right. Then divide across by the x coefficient. Remember that when you move a quantity from one side to the other, its sign changes. Some people describe this as subtracting x from both sides and 3 from both sides - same difference. In your example.......

2x + 3 = x + 9
2x - x = 9 - 3
x = 6

Another example:
6y + 15 = 3y - 3
6y - 3y = -3 -15
3y = -18
y = - 6

OK?

ill try and type this as best i can

2x+3=x+9
take "x" from both sides
2x+3-x=x+9-x
1x+3=9
take 3 from both side
1x+3-3=9-3
1x=6

2x + 3 = x + 9


(-x) (-x)

x + 3 = 9

(- 3) (- 3)

x = 6

2x= x + 6
= 2x - x = 6
x = 6