Factorization: -3x^2-10x+8?
回答 (4)
2008-11-16 1:47 pm
✔ 最佳答案
f = -3x^2-10x+8-f/3 = x^2 +(10/3x) -8/3
x = -5/3 +-sqrt(25/9 +8/3) = -5/3 +- 7/3 = 2/3 or -4
= (x - 2/3)(x+12/3)
f = -(3x - 2)(x+4)
2008-11-16 10:39 pm
-3x^2 - 10x + 8
= -3x^2 + 2x - 12x + 8
= (-3x^2 + 2x) - (12x - 8)
= -x(3x - 2) - 4(3x - 2)
= (3x - 2)(-x - 4)
= -(3x - 2)(x + 4)
= -3x^2 + 2x - 12x + 8
= (-3x^2 + 2x) - (12x - 8)
= -x(3x - 2) - 4(3x - 2)
= (3x - 2)(-x - 4)
= -(3x - 2)(x + 4)
2008-11-16 9:38 pm
Factors of -3x^2 are (-3x,x) or (3x, -x)
Factors of 8 are (4,2) or (-4,-2)
-3x^2-10x+8 = (-3x + 2)(x +4)
Factors of 8 are (4,2) or (-4,-2)
-3x^2-10x+8 = (-3x + 2)(x +4)
2008-11-16 9:31 pm
-3x^2-10x+8
-(x^2 + 10x - 8) = -(x + 4)(3x - 2)
-(x^2 + 10x - 8) = -(x + 4)(3x - 2)
收錄日期: 2021-05-01 11:31:35
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