r = 100(2-cosθ)
點搵dr/dθ同d2r/dθ2呀?
(即d一次and d兩次).
Thanks
Maths: Differentiation
2008-11-16 5:41 am
回答 (1)
2008-11-21 1:15 am
✔ 最佳答案
r = 100(2-cosθ)dr/dθ=d/dθ (200)-d/dθ(200cosθ)
= 200sinθ [dcosθ出-sinθ,d常數就出0]
d^2r/dθ^2姐係將佢d多一次
d^2r/dθ^2=200cosθ
收錄日期: 2021-04-13 18:54:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081115000051KK02027