因式分解(有步驟)20分

2008-11-14 8:11 am
ax-a[2]/a-b   +   bx-ab/b-a

1/a+b   -   3/2b

x+4y/-2x(x-2y )   +  1/3x

5/4x+6  -   7/6x+9

2x+y/x-y   +   y/2y-2x   -   x/x-y

*[2]=二次方
*/=分數果條線(分線)

回答 (1)

2008-11-14 11:16 am
✔ 最佳答案
1) ax-a[2]/a-b   +   bx-ab/b-a
= a(x-a)/a-b + b(x-a)/b-a
= a(x-a)-b(x-a)/a-b
= (a-b)(x-a)/a-b
= x-a

2) 1/a+b   -   3/2b
= 2b-3(a+b)/2b(a+b)
= 2b-3a-3b/2b(a+b)
= -3a-b/2b(a+b)
= -(3a+b)/2b(a+b)

3) x+4y/-2x(x-2y )   +  1/3x
= 3x(x+4y)-2x(x-2y)/-6x[2](x-2y)
= x[2]+16xy/-6x[2](x-2y)
= x(x+16y)/-6x[2](x-2y)
= x+16y/-6(x-2y)

4) 5/4x+6  -   7/6x+9
= 5/2(2x+3) - 7/3(2x+3)
= 15-14/6(2x+3)
=1/6(2x+3)

5) 2x+y/x-y   +   y/2y-2x   -   x/x-y
= 2x+y/x-y - y/2(x-y) - x/x-y
= 2(2x+y) - y - 2x /2(x-y)
=4x+2y-y-2x/2(x-y)
=2x-y/2(x-y)
參考: 自己做


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