multiply (5x-4y)(2x-y)?
回答 (8)
2008-11-13 2:45 pm
✔ 最佳答案
treat one as a monomial:(5x - 4y)(2x - y) = (5x - 4y)(2x)+(5x - 4y)(- y)
= 10x^2 - 8xy - 5xy + 4y^2
= 10x^2 -13xy + 4y^2
2016-12-18 5:04 am
5x ( 6x^2 + 2x -a million) - y ( 6x^2 + 2x -a million) = 30x^3 + 10x^2 - 5x -6x^2y -2xy +y =10x^2 (3x+a million) - 5x + y - 6x^2y -2xy =10x^2 (3x+a million) - 5x +y - 2xy (3x +a million) =10x^2 (3x+a million) - 2xy (3x +a million) - 5x +y =(10x^2 - 2xy)(3x +a million)-5x + y
2008-11-13 5:36 pm
(5x-4y)(2x-y)
=(5x*2x)+(5x*-y)+(-4y*2x)+(-4y*-y)
=10x^2 - 5xy - 8xy + 4y^2
=10x^2 + 4y^2 - 13xy
=(5x*2x)+(5x*-y)+(-4y*2x)+(-4y*-y)
=10x^2 - 5xy - 8xy + 4y^2
=10x^2 + 4y^2 - 13xy
2008-11-13 3:42 pm
(5x - 4y)(2x - y)
= 5x*2x - 4y*2x - 5x*y + 4y*y
= 10x^2 - 8xy - 5xy + 4y^2
= 10x^2 - 13xy + 4y^2
= 5x*2x - 4y*2x - 5x*y + 4y*y
= 10x^2 - 8xy - 5xy + 4y^2
= 10x^2 - 13xy + 4y^2
2008-11-13 2:49 pm
10x^2-5xy-8xy+4y^2
10x^2-14xy+4y^2
10x^2-14xy+4y^2
2008-11-13 2:40 pm
= 10x^2 - 5xy - 8xy + 4y^2 = 10x^2 - 13xy + 4y^2
2008-11-13 2:37 pm
you just do it term by term
(5x-4y)(2x-y)
10x² – 5xy – 8xy + 4y²
10x² – 13xy + 4y²
.
(5x-4y)(2x-y)
10x² – 5xy – 8xy + 4y²
10x² – 13xy + 4y²
.
2008-11-13 2:37 pm
10x-4y
IDK something like that
IDK something like that
收錄日期: 2021-05-01 11:31:26
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