因式分解以下題目

2008-11-13 3:29 am

(8x^3 - 1)- 2x+1 ( ^3 = 3次方 )

回答 (3)

2008-11-13 5:02 am

✔ 最佳答案

(8x^3-1)-2x+1
=(2x-1)(4x^2+2x+1)-(2x-1)
=(2x-1)(4x^2+2x)
=2x(2x+1)(2x-1)

2008-11-12 21:04:41 補充：
(8x^3-1)-2x+1
=8x^3-2x
=2x(4x^2-1)
=2x(2x+1)(2x-1)

參考: ME

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2008-11-14 1:06 am

(8x^3 - 1)- 2x+1
= 8x^3 - 1 - 2x+1.........拆括號
=8x^3 - 2x
=2x(4x²-1)...........抽公因數
=2x[(2x)²-(1)²]
=2x(2x-1)(2x+1)............a²-b²=(a-b)(a+b)

參考: 會考數學拿c既人~

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2008-11-13 3:52 am

(8x^3-1)-2x+1
=(2x-1)(4x^2+2x+1)-(2x-1)
=(2x-1)(4x^2+2x)
=2(2x-1)(2x^2+x)

參考: 我自己

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