Simplify: ?

[(2x - 3)(5x + 5)]/[5x(2x^2-x-3)]
[10x^2 -5x -15]/[10x^3-5x^2-6x]

First factorize 2x^2 - x - 3 = 2x^2 - 3x + 2x - 3 = x(2x-3) +1(2x-3)
=(2x-3)(x+1) = (2x-3)(x+1)

(2x-3)/(5x) * (5x+5)/(2x^2 - x - 3)
=[(2x-3)*(5x+5)]/[(5x)(2x^2 - x - 3)]
=[5*(2x-3)(x+1)]/[(5x)(2x-3)(x+1)]
= 5/(5x)
= 1/x

(2x - 3)/5x * (5x + 5)/(2x^2 - x - 3)
= (2x - 3)/5(x) * 5(x + 1)/(2x^2 + 2x - 3x - 3)
= (2x - 3)/5(x) * 5(x + 1)/(x + 1)(2x - 3)
= (2x - 1)/x * 1/(2x - 3)
= 1/x * 1
= 1/x

Assuming that should read as :-
[ (2x - 3) / 5x ] [ (5x + 5) / (2x² - x - 3) ]
[ (2x - 3) / 5x ] [ (5 (x + 1) / (2x - 3) (x + 1) ]

(2x - 3) 5 (x + 1)
-------------------------
5x (2x - 3) (x + 1)

1
---
x