How do l solve this one 2x=3(2 is raised to power x)?
回答 (6)
2008-11-10 8:45 am
✔ 最佳答案
2^x=3log 2^x=log 3
by power rule
x log 2= log 3
so x=log 3/ log 2
x= 1.585
2008-11-10 8:46 am
Use a graphing device to graph 2x - 3*2^x and find where it crosses the x intercept
http://www.coolmath.com/graphit/
NEVER!
No solution
Unless you wanted 2^x = 3??
take log of both sides
log(2^x) = log3
x log 2 = log 3
x = log 3 / log 2
x = 1.58 (2dp)
http://www.coolmath.com/graphit/
NEVER!
No solution
Unless you wanted 2^x = 3??
take log of both sides
log(2^x) = log3
x log 2 = log 3
x = log 3 / log 2
x = 1.58 (2dp)
2008-11-10 8:55 am
introducing log to both sides it gives
xlog2=log3
x=log3/log2.............dividing both sides by log2
xlog2=log3
x=log3/log2.............dividing both sides by log2
2008-11-10 8:50 am
2 raised to power x is written as 2^x
so we use the ln (or log decimals)
remember ln a^x = a * lnx
and x ln2 = ln 3
x= ln3/ln2=1.585
so we use the ln (or log decimals)
remember ln a^x = a * lnx
and x ln2 = ln 3
x= ln3/ln2=1.585
2008-11-10 11:28 am
2^x = 3
x log 2 = log 3
x = log 3 / log 2
x = 1.585 (any log base may be used)
x log 2 = log 3
x = log 3 / log 2
x = 1.585 (any log base may be used)
2008-11-10 10:28 am
2^x = 3
x = log₂(3)
x = log(3)/log(2)
x ≈ 1.5849
x = log₂(3)
x = log(3)/log(2)
x ≈ 1.5849
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