1. 一箱雞蛋有8%的雞蛋是壞的 , 從該箱蛋中隨機抽出三隻 , 求抽得兩隻壞蛋的概率。(取答案準確至三位有效數字。)
2. 投擲兩粒均質的骰子 , 考慮以下事件 :
事件E : 點數之積為奇數
若已知擲得的其中一個點數是3 , 求事件E的概率。
中五數學 - 概率
2008-11-09 7:35 am
回答 (2)
2008-11-09 9:10 am
✔ 最佳答案
1. 3 x 0.08 x 0.08 x (1 - 0.08) = 0.017664 = 0.01772. 因知其中一個點數是3, 要令點數之積為奇數的話, 之後既點數一定是奇數。
所以，若已知擲得的其中一個點數是3 ，事件E的概率 = 3/6 = 1/2
參考: Myself
2008-11-09 9:08 am
1. probability = (0.08 x 0.08 x 0.92) x 3
= 0.017664
= 0.0177
2. product of number is odd => all numbers are odd.
condition is one dice is 3, therefore probability of product of numbers is odd
= probability of all numbers are odd with one dice is 3
= probability of remaining 2 dices are odd
= 1/2 x 1/2
= 1/4
= 0.017664
= 0.0177
2. product of number is odd => all numbers are odd.
condition is one dice is 3, therefore probability of product of numbers is odd
= probability of all numbers are odd with one dice is 3
= probability of remaining 2 dices are odd
= 1/2 x 1/2
= 1/4
參考: 自己
收錄日期: 2021-04-24 01:09:33
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