cd``-c``d-c+d
``=２次方
請詳細列式~
F.2因式分解X1
2008-11-05 3:11 am
回答 (3)
2008-11-05 3:18 am
✔ 最佳答案
^2=２次方cd^2-c^2d-c+d
=-c-c^2d+d+cd^2
=-c(1+cd)+d(1+cd)
=(d-c)(1+cd)
參考: 我自己
2008-11-07 4:30 am
cd^2-c^2d-c+d
=cd(d-c)-(c-d) 用併項法,左邊抽cd右邊抽個負號
=cd(d-c)+(d-c) -(c-d) = +(d-c)
=(d-c)(cd+1) 抽個(d-c)出來唷**
2008-11-06 20:31:39 補充：
^ 呢個係代表次方
所以 cd^2 姐係cd``
=cd(d-c)-(c-d) 用併項法,左邊抽cd右邊抽個負號
=cd(d-c)+(d-c) -(c-d) = +(d-c)
=(d-c)(cd+1) 抽個(d-c)出來唷**
2008-11-06 20:31:39 補充：
^ 呢個係代表次方
所以 cd^2 姐係cd``
2008-11-05 4:24 am
cd``-c``d-c+d = cd²-c²d-c+d
=cd(d-c)+(-c+d)
=cd(d-c)+(d-c)
=(d-c)(cd+1)
=cd(d-c)+(-c+d)
=cd(d-c)+(d-c)
=(d-c)(cd+1)
參考: 會考數學拿c既人~
收錄日期: 2021-04-29 16:12:35
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