MATH F.2

2008-11-05 3:03 am

Expand the folloeing expression .

1.(t+1)^2(t-1)^2

=?

要所有步驟呀!!!!!!!!!

吾該

回答 (4)

2008-11-05 3:07 am

✔ 最佳答案

(t+1)^2(t-1)^2
= [(t+1)(t-1)]^2
= (t^2-1)^2
= t^4-2t^2+1

參考: 我喲~~

👍 0 👎 0

2008-11-09 10:48 am

(t+1)^2 (t-1)^2
= [(t+1)(t-1)]^2
= (t^2-1)^2
= (t^2)^2-2(t^2)(1)+(1)^2
= t^4-2t^2+1

👍 0 👎 0

2008-11-09 3:32 am

(t+1)^2(t-1)^2
=[(t+1)(t-1)]^2
=[t(t-1)+(t-1)]^2
=(t^2-t+t-1)^2
=t^4-1

參考: 同是F.2的人

👍 0 👎 0

2008-11-05 4:29 am

(t+1)^2(t-1)^2 = (t+1)²(t-1)²

=[(t+1)(t-1)]².............a²b²=(ab)²
=(t²-1)²...........(a+b)(a-b)=a²-b²
=t^4-2t²+1........(a-b)²=a²-2ab+b²

參考: 會考數學拿c既人~

👍 0 👎 0