有D Fatorization 數學吳識計, 幫幫拖!!!

(x+y)²z²-4(x+y)(x-y)z²+2(x-y)²z²
=z²[(x+y)²-4(x+y)(x-y)+2(x-y)²]..........抽公因數
=z²[(x+y)²-2(2)(x+y)(x-y)+2(x-y)²].........係吳係打錯野.? 2(x-y)²=4(x-y)²先得



=z²[(x+y)²-2(2)(x+y)(x-y)+4(x-y)²]
=z²{(x+y)²-2(2)(x+y)(x-y)+[2(x-y)]²}.............a²b²=(ab)²
=z²{(x+y)-[2(x-y)]}²
=z²[x+y-(2x-2y)]²
=z²(x+y-2x+2y)²
=z²(3y-x)²
=[z(3y-x)]².............a²b²=(ab)²

(x+y)2z2-4(x+y)(x-y)z2+2(x-y)2z2
=z2[(x+y)2-4(x+y)(x-y)+2(x-y)2]

你個fatorization串錯字,係factorization,同factorize.