Factorise x^2 + 7x + 10x?

x^2 + 17x
x(x+17)


.

x^2 + 7x + 10x
= x^2 + 17x
= x(x + 17)

But I assume it should be x^2 + 7x + 10.
x^2 + 7x + 10
= x^2 + 5x + 2x + 10
= (x^2 + 5x) + (2x + 10)
= x(x + 5) + 2(x + 5)
= (x + 5)(x + 2)

x^2 + 7x + 10x
=x(x+7+10)
=x(x+17)

that is the answer
....

x² - 10x + 21 discover 2 numbers whose product is 21 yet whose sum is -10. those 2 numbers are -7 and -3. (x - 7)(x - 3) once you multiply the 1st words, you get x² once you multiply the interior and outdoors words, you get -7x - 3x. in view that they have the comparable variable, you may combine them into -10x once you multiply the final words, you get 21 x² + 7x + 10 discover 2 numbers whose product is 10 yet whose sum is 7. those 2 numbers are 5 and a pair of (x + 5)(x + 2) undergo in recommendations the interior and outdoors words are blended, so which you get 5x + 2x, this is 7x., and the final words finally end up 10. answer (x - 7)(x - 3) (x + 5)(x + 2)

Question Number 1 :
For this equation x^2 + 7*x + 10 = 0 , answer the following questions :
A. Use factorization to find the root of the equation !

Answer Number 1 :
The equation x^2 + 7*x + 10 = 0 is already in a*x^2+b*x+c=0 form.
By matching the constant position, we can derive that the value of a = 1, b = 7, c = 10.

1A. Use factorization to find the root of the equation !
x^2 + 7*x + 10 = 0
( x + 2 ) * ( x + 5 ) = 0
The answers are x1 = -2 and x2 = -5

I'm guessing you actually mean:

x^2 + 7x + 10
(x + 5)(x + 2)

hah i love these (:

know that: when you factorize an expression you always put the GCF on the outside, and put the other "stuff" inside. you'll see what i mean in a second--

x^2 + 7x + 10x
they all have X in common. and that's ALL they have in common.

x(x + 7 + 10)
all i did was put x on the outside of the parenthesis and put the other "stuff" on the inside. now-- when you multiply it out, see if you get the original problem.

x times x = x^2 +
x times 7 = 7x +
x times 10 = 10x +

x^2 + 7x + 10x

(:

X(X+17)

x^2 + 7x + 10x =
x^2 +17x
factor x to get
x(x+17)

x(x +7+10)
x(x+17)

x^2+7x+10x= x^2+17x= (x+17)*x