我唔識Maths(5)

2008-11-02 6:06 am
A=3Y-X-YX二次方

a) 如果A=-9 , X=-3 , 求Y的值.

解以下方程式.

x 2x 4
--- - --- = ---
3 5 15


+解釋 thx 送5點給你!

回答 (4)

2008-11-02 7:58 am
✔ 最佳答案
A=3Y-X-YX²
-9=3Y-(-3)-Y(-3)²
-9=3Y+3-9Y
-12=-6Y
Y=2



x 2x 4
--- - --- = x/3 - 2x/5 -4/15
3 5 15

=(5x-6x-4)/15
=(-x-4)/15


如果(-x-4)/15=0
-x-4=0
x=4
參考: 會考數學拿c既人~
2008-11-02 2:37 pm
係咪咁呀?
第一條:

A=3Y-X-YX

(-9)=3Y-(-3)-(-3Y)

(-12)=6Y

(-12)/6=Y

-2=Y

Y=-2
 ===

第二條:

2x/35-4x/15

=(-6)/35-(-12)/15

=[(-18)-(-84)]/105

=66/105

=22/35
 ====

2008-11-02 06:37:41 補充:
係咪咁呀?
第一條:

A=3Y-X-YX

(-9)=3Y-(-3)-(-3Y)

(-12)=6Y

(-12)/6=Y

-2=Y

Y=-2
 ===

第二條:

2x/35-4x/15

=(-6)/35-(-12)/15

=[(-18)-(-84)]/105

=66/105

=22/35
 ====
參考: 自己
2008-11-02 8:01 am
我都係....

唔明...

你第二條想問D咩??
2008-11-02 6:22 am
As follow AS~~~

圖片參考:http://www.photo-host.org/img/706004screenhunter_01_nov._01_22.16.gif


2008-11-01 22:22:21 補充:
第2題唔明你問乜

2008-11-02 07:34:41 補充:
(x/3) - (2x/5) = 4/15
5x-3(2x)=4
5x-6x=4
-x=4
x=-4


收錄日期: 2021-04-23 20:34:51
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