general term

2008-11-01 4:56 pm
1,2,4,7,11,16...

please find the general term.
更新1:

最好加埋步驟

回答 (2)

2008-11-01 7:18 pm
✔ 最佳答案
General term is (n^2 - n + 2)/2.

2008-11-01 13:33:43 補充:
16 = 15 + 1 = 6 x 5/2 + 1
11 = 10 + 1 = 5 x 4/2 + 1
7 = 6 + 1 = 4 x 3/2 + 1
4 = 3 + 1 = 3 x 2/2 + 1
2 = 1 + 1 = 2 x 1/2 + 1
1 = 0 + 1 = 1 x 0/2 + 1
2008-11-01 5:07 pm
The n term is
Summation i=1 to n [Summation j=1 to j (j)]

2008-11-01 09:07:43 補充:
sorry, typo
Summation i=1 to n [Summation j=1 to i (j)]


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