what is the prime factorization of 56?

56 = 2 x 2 x 2 x 7

or

56 = 2^3 x 7

Prime Factorization Of 56

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1 X 56 2 X 28 4 X 14

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RE:
what is the prime factorization of 56?

56 =
7 * 8
7 * 2 * 4
7 * 2 * 2 * 2



.

why not 3^3*2.

remember if u want to find number of factors for a number express it in the terms of product of co-primes.
suppose the factorization is expressed as 3^m*5^n.
then the no. of factors for the given number is (m+1)(n+1).

56 = 8 x 7
= 2 x 2 x 2 x 7
the prime factors are 2 and 7

56=2^3 x 7

56=7(2^3)

since it's even we know it has a factor of 2:
56/2=28
since 28 is even we know it has a second factor of 2:
28/2=14
since 14 is even we know it has a third factor of 2:
14/2=7
and 7 is prime. So your prime factors are 2,2,2,7