3x-r=r(-3+x)
Please explain how to isolate x in this equation!THANKS!
Solving for x in the equation?
2008-10-31 5:03 am
回答 (4)
2008-10-31 5:13 am
✔ 最佳答案
3x-r=r(-3+x) original equation3x-r=-3r+xr multiply
3x=-2r+xr add r to both sides
3x-xr=-2r subtract xr from both sides
x(3-r)=-2r factor out x on left side
x=-2r/(3-r) divide
2008-10-31 5:11 am
3x - r = r(-3 + x)
3x - r = r(x - 3)
3x - r = r*x - r*3
3x - r = rx - 3r
3x - rx = r - 3r
x(3 - r) = -2r
x = -2r/(3 - r)
3x - r = r(x - 3)
3x - r = r*x - r*3
3x - r = rx - 3r
3x - rx = r - 3r
x(3 - r) = -2r
x = -2r/(3 - r)
2008-10-31 5:11 am
3x - r = r(-3 + x)
3x - r = rx - 3r
3x - rx = -2r
(3 - r)x = -2r
x = 2r / (r - 3)
3x - r = rx - 3r
3x - rx = -2r
(3 - r)x = -2r
x = 2r / (r - 3)
2008-10-31 5:10 am
Firstly try and get all the xs to one side.
Expand the brackets:
3x - r = -3r + rx
Move the -r to the RHS and the rx to the LHS:
3x - rx = -3r + r
Factorise the LHS and simplify the RHS
x(3 - r) = -2r
Divide both sides by (3 - r)
x = -2r/(3 - r)
Done.
Expand the brackets:
3x - r = -3r + rx
Move the -r to the RHS and the rx to the LHS:
3x - rx = -3r + r
Factorise the LHS and simplify the RHS
x(3 - r) = -2r
Divide both sides by (3 - r)
x = -2r/(3 - r)
Done.
收錄日期: 2021-05-01 11:26:44
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