Divide y2 + 13y + 22 by y + 2?

y^2 + 13y + 22
---------------------
(y+2)


(y+2)(y+11)
-----------------
(y+2)


(y+11)



.

= (y² + 13y + 22)/(y + 2)
= ([y + 11][y + 2])/(y + 2)
= y + 11

Answer: y + 11

y+11

the 1st step is to factor each little thing. (y² + 13y + 40 two) / (y² + 15y + fifty 4) factor the numerator and denominator ((y + 6)(y + 7)) / ((y + 9)(y + 6)) because of the fact that we've a (y + 6) in the numerator and denominator you could desire to cancel them, because of the fact that something divided by using itself is one, desirable. (y + 7) / (y + 9) because of the fact that (y + 7) / (y + 9) can't be factored anymore, we are accomplished. i'm hoping this helps. Have a good day.

y + 11

(y^2 + 13y + 22)/(y + 2)
= (y^2 + 11y + 2y + 22)/(y + 2)
= [(y^2 + 11y) + (2y + 22)]/(y + 2)
= [y(y + 11) + 2(y + 11)]/(y + 2)
= (y + 11)(y + 2)/(y + 2)
= y + 11

To solve the problem, first factor (y2+13Y+22). This will be (y+11)(y+2).
Dividing by (y+2) will be y+11 as the y+2/y+2 = 1. And 1 (y+11) = y+11.

y_2+13 y+2+22/y

Divide y² + 13y + 22 by y + 2
Divide (y + 11)(y +2) by y + 2
Answer is (y + 11)

y^2 +13y +22=(y+2)(y+11)
(y+2)(y+11) / (y+2)=y+11