Divide x2 + 10x + 21 by x + 3?
回答 (6)
2008-11-03 4:18 am
✔ 最佳答案
x^2 + 10 + 21--------------------
.....(x+3)
(x+3)(x+7)
---------------
(x+3)
(x+7)
.
2008-10-30 2:48 pm
Divide x2 + 10x + 21 by x + 3
Divide (x + 3)(x + 7) by x + 3
Answer = x + 7
Divide (x + 3)(x + 7) by x + 3
Answer = x + 7
2008-10-30 2:48 pm
Simplifying x^2+10x+21
x^2 + 10x + 21=
= x^2 + 3x + 7x + 21
= x(x + 3) + 7 (x + 3)
= (x + 3)(x + 7)
Dividing the above by (x + 3) is simple -->
(x + 3)(x + 7) / (x + 3)
= x + 7
x^2 + 10x + 21=
= x^2 + 3x + 7x + 21
= x(x + 3) + 7 (x + 3)
= (x + 3)(x + 7)
Dividing the above by (x + 3) is simple -->
(x + 3)(x + 7) / (x + 3)
= x + 7
2008-10-30 4:26 pm
(x^2 + 10x + 21)/(x + 3)
= (x^2 + 7x + 3x + 21)/(x + 3)
= [(x^2 + 7x) + (3x + 21)]/(x + 3)
= [x(x + 7) + 3(x + 7)]/(x + 3)
= (x + 7)(x + 3)/(x + 3)
= x + 7
= (x^2 + 7x + 3x + 21)/(x + 3)
= [(x^2 + 7x) + (3x + 21)]/(x + 3)
= [x(x + 7) + 3(x + 7)]/(x + 3)
= (x + 7)(x + 3)/(x + 3)
= x + 7
2008-10-30 3:00 pm
x+7
2008-10-30 2:58 pm
x11
收錄日期: 2021-05-01 11:27:56
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