FACTORIAZATION BY GROUPING TERMS
ax-ay-by+by
要有埋STEP!
form 2 MATH
2008-10-31 5:49 am
回答 (7)
2008-10-31 7:58 am
✔ 最佳答案
係ax-ay-by+by定係ax-ay-by+byax-ay-by+by
=ax-ay
=a(x-y)
ax-ay-bx+by
=a(x-y)-b(x+y)
=a(x-y)+b(x-y)
=(a+b)(x-y)
如果唔明email me=]
參考: myself=]scored a1 for math^_^
2008-10-31 8:21 pm
ax-ay-by+by
=a(x-y)
你有冇打錯ar?
ax-ay-by+bx
=a(x-y)+b(x-y)
(x-y)(a+b)
ax-ay-bx+by
=a(x-y)-b(x-y)
(x-y)(a-b)
=a(x-y)
你有冇打錯ar?
ax-ay-by+bx
=a(x-y)+b(x-y)
(x-y)(a+b)
ax-ay-bx+by
=a(x-y)-b(x-y)
(x-y)(a-b)
參考: 自己
2008-10-31 6:34 am
2008-10-31 6:13 am
ax-ay-by+by
=a(x-y)
你係咪打錯左呀
係咪應該ax-ay-bx+by?
如果真係既話應該咁做
ax-ay-bx+by
=a(x-y)-b(x-y)
=(x-y)(a-b)
=a(x-y)
你係咪打錯左呀
係咪應該ax-ay-bx+by?
如果真係既話應該咁做
ax-ay-bx+by
=a(x-y)-b(x-y)
=(x-y)(a-b)
參考: myself
收錄日期: 2021-05-02 16:50:23
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