form 2 MATH

2008-10-31 5:49 am
FACTORIAZATION BY GROUPING TERMS



ax-ay-by+by

要有埋STEP!

回答 (7)

2008-10-31 7:58 am
✔ 最佳答案
係ax-ay-by+by定係ax-ay-by+by
ax-ay-by+by
=ax-ay
=a(x-y)


ax-ay-bx+by
=a(x-y)-b(x+y)
=a(x-y)+b(x-y)
=(a+b)(x-y)

如果唔明email me=]
參考: myself=]scored a1 for math^_^
2008-10-31 11:02 pm
ax-ay-by+by

=ax-ay

=a(x-y)
參考: Me
2008-10-31 8:21 pm
ax-ay-by+by
=a(x-y)

你有冇打錯ar?
ax-ay-by+bx
=a(x-y)+b(x-y)
(x-y)(a+b)

ax-ay-bx+by
=a(x-y)-b(x-y)
(x-y)(a-b)
參考: 自己
2008-10-31 6:35 am
ax-ay-by+by
=a(x-y)-by(1+1)
參考: myself
2008-10-31 6:34 am
ax-ay-by+by
= ax-ay
= a(x-y)
圖片參考:http://tw.yimg.com/i/tw/ugc/rte/smiley_4.gif
2008-10-31 6:13 am
ax-ay-by+by
=a(x-y)

你係咪打錯左呀
係咪應該ax-ay-bx+by?
如果真係既話應該咁做

ax-ay-bx+by
=a(x-y)-b(x-y)
=(x-y)(a-b)
參考: myself
2008-10-31 5:56 am
ax-ay-by+by
= a(x-y)//

-by+by = 0 唔洗寫"
參考: me


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