求以下數列的弟八項:
4,9,16,25,．．．
求以下數列的通項Ｔn
11,101,1001,10001,．．．
數列．．好急．10分
2008-10-30 2:57 am
回答 (3)
2008-10-30 3:13 am
✔ 最佳答案
1. 4 = 2^2 = (1+1)^29 = 3^2 = (2+1)^2
T8 = (8+1)^2 = 81
2.
11 , 101 , 1001 , 10001
11 = 10 + 1
101 = 100 + 1
1001 = 1000 + 1
Tn = 10^n + 1
收錄日期: 2021-04-13 16:12:40
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081029000051KK01082