Need this factored also need work shown x(x-12)+ -27?

x^2 -12x -27=(x-13.93725)(x+1.93725)

x(x - 12) + 27
= x*x - x*12 + 27
= x^2 - 12x + 27
= x^2 - 3x - 9x + 27
= (x^2 - 3x) - (9x - 27)
= x(x - 3) - 9(x - 3)
= (x - 3)(x - 9)

first, convert it into a quadratic equation of the form ax^2+bx+c=0
In this case, 1x^2-12x+27 Or maybe -27. I can't figure it out because you have both written.

if it's +27, then just find the factors of 1*27 that add up to -12, -9 and -3. The equation then becomes (x-9)(x-3)=0, or x=3 and x=9

If it's -27, then it's a little harder. Start by plugging into the quadratic formula, x=(-b±sqrt(b^2-4ac))/(2a), in this case x=(12±sqrt(144+108))/2. This comes out ugly, but is x=13.94 or x=-1.94

x(x-12)+ -27 = x^2-12x - 27

[12+/-(144+ 4*27)^(1/2)]/2 = 6+/ - (63)^1/2

(x - (6+(63)^1/2))(x -(6 - (63)^1/2))
this is ugly

if
x(x-12)+ 27 = x^2-12x + 27 = (x-3)(x-9)

x(x-12)+-27
x^2-12x+-27
x^2-12x-27
(x-3)(x+9) -answer
that's the answer =]

x(x-12)+ -27
= x^2 - 12x + 27
= (x - 3)(x - 9)

are you sure its -27? and not + 27 ?