有無人識計...F.3數 因式分解

1.
16x²-4y²+12y-9
=(4x)²-(2y-3)²
=(4x+2y-3)(4x-2y+3)

2. 你打錯野啊- -跟本因式分解吳倒= =|
x²-y²+4x+8y-12
=(x-y)(x+y)+4(x+2y-3)....無得玩- -

x²-y²+4x+8y-12
=(x-2)(x+6)-y²+8y......都係無得玩- -

1.

16x^2-4y^2+12y-9
=(4x)^2-(4y^2-12y+9)
=(4x)^2-(2y-3)^2
=(4x+2y-3)(4x-2y+3)

2.

x^2-y^2+4x+8y-12
=x^2+4x+4-y^2+8y-16
=(x^2+4x+4)-(y^2-8y+16)
=(x+2)^2-(y-4)^2
=(x+2+y-4)(x+2-y+4)

注：
a^2-b^2=(a+b)(a-b)
(a+b)^2=a^2+2ab+b^2
(a-b)^2=a^2-2ab+b^2

2008-10-28 22:13:11 補充：
sorry...漏野...

2. (續)
...
...
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=(x+2+y-4)(x+2-y+4)
=(x+y-2)(x-y+6)

如果還不明白，歡迎給e-mail我，我會盡量為你解答。

第二題:=(x平方+4x+4)-(y平方-8y+16)
=(x+2)平方-(y-4)平方
=(x+2+y-4)(x+2-y+4)
=(x+y-2)(x-y+6)

第一題:=16x平方-(4y平方-12y+9)
=16x平方-(2y-3)平方
=(4x+2y-3)(4x-2y+3)

1.16x既2次-4y既2次+12y-9
=16x既2次-(2y+3)既2次
=(4x+2y+3)(4x-2y-3)
2.x既2次-y既2次+4x+8y-12
=4(x+y)(x-y)(x+2y-3)