hey can you help me with my math ?
回答 (4)
2008-10-27 11:30 am
✔ 最佳答案
2y + 4(y - 1) - 2 / y - 12y + 4y - 4 - 2 / y - 1
6y - 6/ y - 1
factorize the above
6(y - 1)/y - 1
y - 1 cancel out y - 1
Therefore answer = 6.
參考: Based on user's experience
2008-10-27 12:01 pm
[2y + 4(y - 1) - 2]/(y - 1)
= (2y + 4*y - 4*1 - 2)/(y - 1)
= (2y + 4y - 4 - 2)/(y - 1)
= (6y - 6)/(y - 1)
= 6(y - 1)/(y - 1)
= 6/1
= 6
= (2y + 4*y - 4*1 - 2)/(y - 1)
= (2y + 4y - 4 - 2)/(y - 1)
= (6y - 6)/(y - 1)
= 6(y - 1)/(y - 1)
= 6/1
= 6
2008-10-27 11:46 am
2y+4(y-1)-2 over y-1
= 2y + 4y -- 4 -- 2 over y -- 1
= 6(y -- 1) over (y -- 1)
= 6
= 2y + 4y -- 4 -- 2 over y -- 1
= 6(y -- 1) over (y -- 1)
= 6
2008-10-27 11:31 am
[2y+4(y-1)-2]/(y-1)
= (2y+4y-4-2)/(y-1)
= (6y-6)/(y-1)
= 6(y-1)/(y-1)
= 6
= (2y+4y-4-2)/(y-1)
= (6y-6)/(y-1)
= 6(y-1)/(y-1)
= 6
收錄日期: 2021-05-01 11:26:08
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